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== `sum_0^oo ` mathHandbook.com

+ - * / ^ ! o `oo` `alpha` `beta` `gamma` `Gamma` `theta` `pi` ( ) ,
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f(x) = x; `sum_(x=0)^oo`f(x) `int`y(x) dx `int y(x) (dx)^0.5` `int_0^1` sin(x) dx `d/dx`y(x) `(d^(1) y)/dx^(1)` y' `y^((1))(x)`








Input:
dsolve(y(2,x)-y(1,x)*y-2x)

Write:
`dsolve(y(2,x)-y(1,x)*y-2x)`



Compute: $$dsolve(y^{(2)}(x)-y^{(1)}(x)\ y-2\ x)$$

Output: $$ dsolve(y^{(2)}(x)-y^{(1)}(x)\ y-2\ x) == (\sqrt {-2})\ x\ and\ (\sqrt {-2})\ x-\frac {2}{x} $$ Result:$$(\sqrt {-2})\ x\ and\ (\sqrt {-2})\ x-\frac {2}{x}$$



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