Input:
pdsolve(ds(y,t,1.5)=ds(y,x,1.5)-2y^2-4x*y-2x^2)
Write:
`pdsolve(ds(y,t,1.5)=ds(y,x,1.5)-2y^2-4x*y-2x^2)`
Compute:
$$pdsolve(\frac{d^{{1.5}}y}{dt^{{1.5}}}=\frac{d^{{1.5}}y}{dx^{{1.5}}} - 2\ {y}^{2} - 4\ x\ y - 2\ {x}^{2})$$
Output:
$$pdsolve(\frac{d^{{1.5}}y}{dt^{{1.5}}}=\frac{d^{{1.5}}y}{dx^{{1.5}}} - 2\ {y}^{2} - 4\ x\ y - 2\ {x}^{2})== -x+(-1.1283791670955126i)\ \frac{1}{(C_1+x)^1.5}$$
Result: $$-x+(-1.1283791670955126i)\ \frac{1}{(C_1+x)^1.5}$$
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