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Math Handbook Calculator

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Input:
`d(sin(x),x=1,2)`

Compute:
$$\frac{d^{{2}}}{dx^{2}}|_{x=1} sin(x)$$

Result:
$$sin(1+\pi )$$

LaTeX:
sin(1+\pi )

$$\frac{d^{{2}}}{dx^{2}}|_{x=1} sin(x) == sin(1+\pi )$$




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